0=45x^2+56x-45

Solution for 0=45x^2+56x-45 equation:

0=45x^2+56x-45

We move all terms to the left:

0-(45x^2+56x-45)=0

We add all the numbers together, and all the variables

-(45x^2+56x-45)=0

We get rid of parentheses

-45x^2-56x+45=0

a = -45; b = -56; c = +45;
Δ = b2-4ac
Δ = -562-4·(-45)·45
Δ = 11236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11236}=106$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-106}{2*-45}=\frac{-50}{-90}
=5/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+106}{2*-45}=\frac{162}{-90}
=-1+4/5
$